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-4.19x+0.42x^2=0
a = 0.42; b = -4.19; c = 0;
Δ = b2-4ac
Δ = -4.192-4·0.42·0
Δ = 17.5561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.19)-\sqrt{17.5561}}{2*0.42}=\frac{4.19-\sqrt{17.5561}}{0.84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.19)+\sqrt{17.5561}}{2*0.42}=\frac{4.19+\sqrt{17.5561}}{0.84} $
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